Two opposite and equal charges 4 times 10^{-8 | vedclass

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(D) Given: Charge $q = 4 	imes 10^{-8} \, C$,separation $2a = 2 	imes 10^{-2} \, cm = 2 	imes 10^{-4} \, m$,and electric field $E = 4 	imes 10^8 \

Vedclass · Accepted Answer

$32 	imes 10^{-4} \, Nm$ and $64 	imes 10^{-4} \, J$

Vedclass · Answer

(D) Given: Charge $q = 4 	imes 10^{-8} \, C$,separation $2a = 2 	imes 10^{-2} \, cm = 2 	imes 10^{-4} \, m$,and electric field $E = 4 	imes 10^8 \, N/C$.First,calculate the dipole moment $p = q 	imes (2a) = (4 	imes 10^{-8}) 	imes (2 	imes 10^{-4}) = 8 	imes 10^{-12} \, Cm$.The maximum torque is given by $	au_{\max} = pE = (8 	imes 10^{-12}) 	imes (4 	imes 10^8) = 32 	imes 10^{-4} \, Nm$.The work done in rotating the dipole by $180^o$ is $W = pE(1 - \cos 180^o) = pE(1 - (-1)) = 2pE$.Substituting the values,$W = 2 	imes (32 	imes 10^{-4}) = 64 	imes 10^{-4} \, J$.

Two opposite and equal charges $4 \times 10^{-8} \, C$ are placed $2 \times 10^{-2} \, cm$ apart,forming a dipole. If this dipole is placed in an external electric field of $4 \times 10^8 \, N/C$,what are the values of the maximum torque and the work done in rotating it through $180^o$?

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